Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
nelle | 176 | 18 | 1 | 18.0000 |
In | 305 | 30 | 2 | 15.0000 |
La | 661 | 43 | 3 | 14.3333 |
E | 240 | 14 | 1 | 14.0000 |
Il | 739 | 60 | 5 | 12.0000 |
ma | 659 | 24 | 2 | 12.0000 |
sulla | 220 | 23 | 2 | 11.5000 |
Ma | 173 | 11 | 1 | 11.0000 |
sul | 317 | 21 | 2 | 10.5000 |
Dopo | 101 | 10 | 1 | 10.0000 |
Per | 196 | 17 | 2 | 8.5000 |
A | 219 | 16 | 2 | 8.0000 |
fino | 131 | 8 | 1 | 8.0000 |
allo | 88 | 7 | 1 | 7.0000 |
Una | 152 | 7 | 1 | 7.0000 |
Non | 271 | 17 | 3 | 5.6667 |
nel | 737 | 66 | 13 | 5.0769 |
dove | 148 | 10 | 2 | 5.0000 |
attraverso | 64 | 5 | 1 | 5.0000 |
negli | 87 | 5 | 1 | 5.0000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
stessa | 60 | 1 | 7 | 0.1429 |
sito | 38 | 1 | 7 | 0.1429 |
media | 64 | 1 | 7 | 0.1429 |
padre | 39 | 1 | 6 | 0.1667 |
tutte | 84 | 1 | 6 | 0.1667 |
deciso | 57 | 1 | 6 | 0.1667 |
quali | 59 | 1 | 6 | 0.1667 |
volte | 69 | 1 | 6 | 0.1667 |
Stati | 38 | 1 | 6 | 0.1667 |
strada | 38 | 1 | 6 | 0.1667 |
servizio | 43 | 1 | 6 | 0.1667 |
fase | 48 | 1 | 5 | 0.2000 |
corpo | 33 | 1 | 5 | 0.2000 |
regione | 37 | 1 | 5 | 0.2000 |
carabinieri | 32 | 1 | 5 | 0.2000 |
potuto | 29 | 1 | 5 | 0.2000 |
vendita | 27 | 1 | 5 | 0.2000 |
nuovo | 163 | 2 | 10 | 0.2000 |
realtà | 49 | 1 | 5 | 0.2000 |
vi | 72 | 1 | 5 | 0.2000 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II